我该如何在Swift中拆分JSON字符串？

这个问题已经有了答案:

如何在Swift中将字符串分割成数组？

我正在编写一个应用程序，从Timezonedb API获取可用时区列表：

https://timezonedb.com/references/list-time-zone

我试图解析zoneName，它当前的格式为“欧洲/安道尔”。我的问题是，如何将JSON字符串拆分为仅在表格视图中显示城市名称，即“安道尔”？

这是我收到的响应：

{
"status":"OK",
"message":"",
"zones":[
    {
        "countryCode":"AD",
        "countryName":"Andorra",
        "zoneName":"Europe\/Andorra",
        "gmtOffset":7200,
        "timestamp":1464453737
    },
    {
        "countryCode":"AE",
        "countryName":"United Arab Emirates",
        "zoneName":"Asia\/Dubai",
        "gmtOffset":14400,
        "timestamp":1464460937
    },
    {"
        countryCode":"AF",
        "countryName":"Afghanistan",
        "zoneName":"Asia\/Kabul",
        "gmtOffset":16200,
        "timestamp":1464462737
    }]}

这是我的代码：

Model：

struct TimeZones: Codable {
let status, message: String?
let zones: [Zone]?
}
struct Zone: Codable {
let countryCode, countryName, zoneName: String?
let gmtOffset, timestamp: Int?
}

这是网络编程代码：

var cities: [Zone] = []
   func getAvailableTimeZones() {
    let config = URLSessionConfiguration.default
    let session = URLSession(configuration: config)
    let url = Bundle.main.url(forResource: "data", withExtension: "json")!
    let task = session.dataTask(with: url) { data, response, error in
        // Check for errors
        guard error == nil else {
            print ("error: \(error!)")
            return
        }
        // Check that data has been returned
        guard let content = data else {
            print("No data")
            return
        }
        do {
            let decoder = JSONDecoder()
            decoder.keyDecodingStrategy = .convertFromSnakeCase
            let timeZones = try decoder.decode(TimeZones.self, from: content)
            if let zones = timeZones.zones {
                self.cities.append(contentsOf: zones)
            }
        } catch let err {
            print("Err", err)
        }
    }
    // Execute the HTTP request
    task.resume()
}

TableViewController：

override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "searchResultsCell", for: indexPath)
    cell.textLabel?.text = cities[indexPath.row].zoneName
    return cell
}

任何帮助将不胜感激。谢谢。