如何在Windows Phone 8中使用HttpClient请求发送Post请求体？

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如何在Windows Phone 8中使用HttpClient请求发送Post请求体？

我已经编写了下面的代码来发送头文件、发布参数。问题是我正在使用SendAsync，因为我的请求可以是GET或POST。我该如何添加POST Body到这个代码片段中，以便如果有任何POST Body数据，则将其添加到我进行的请求中，并且如果它是简单的GET或POST而没有Body，则以这种方式发送请求。请更新下面的代码：

HttpClient client = new HttpClient();
// Add a new Request Message
HttpRequestMessage requestMessage = new HttpRequestMessage(RequestHTTPMethod, ToString());
// Add our custom headers
if (RequestHeader != null)
{
    foreach (var item in RequestHeader)
    {
        requestMessage.Headers.Add(item.Key, item.Value);
    }
}
// Add request body
// Send the request to the server
HttpResponseMessage response = await client.SendAsync(requestMessage);
// Get the response
responseString = await response.Content.ReadAsStringAsync();

admin 更改状态以发布 2023年5月24日
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2 答案

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我是用以下方法来实现的。我想要一个通用的MakeRequest方法，它可以调用我的API，并接收请求体中的内容，同时将响应反序列化为所需的类型。我创建了一个Dictionary对象来存储要提交的内容，然后将HttpRequestMessage的Content属性设置为它:

调用API的通用方法:

    private static T MakeRequest(string httpMethod, string route, Dictionary postParams = null)
    {
        using (var client = new HttpClient())
        {
            HttpRequestMessage requestMessage = new HttpRequestMessage(new HttpMethod(httpMethod), $"{_apiBaseUri}/{route}");
            if (postParams != null)
                requestMessage.Content = new FormUrlEncodedContent(postParams);   // This is where your content gets added to the request body
            HttpResponseMessage response = client.SendAsync(requestMessage).Result;
            string apiResponse = response.Content.ReadAsStringAsync().Result;
            try
            {
                // Attempt to deserialise the reponse to the desired type, otherwise throw an expetion with the response from the api.
                if (apiResponse != "")
                    return JsonConvert.DeserializeObject(apiResponse);
                else
                    throw new Exception();
            }
            catch (Exception ex)
            {
                throw new Exception($"An error ocurred while calling the API. It responded with the following message: {response.StatusCode} {response.ReasonPhrase}");
            }
        }
    }

调用该方法:

    public static CardInformation ValidateCard(string cardNumber, string country = "CAN")
    { 
        // Here you create your parameters to be added to the request content
        var postParams = new Dictionary { { "cardNumber", cardNumber }, { "country", country } };
        // make a POST request to the "cards" endpoint and pass in the parameters
        return MakeRequest("POST", "cards", postParams);
    }

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更新2：

来自@Craig Brown：

从.NET 5开始，您可以执行以下操作：
requestMessage.Content = JsonContent.Create(new { Name = "John Doe", Age = 33 });

请参见JsonContent类文档

更新1：

哦，它甚至可以更加出色（来自此答案）：

requestMessage.Content = new StringContent("{\"name\":\"John Doe\",\"age\":33}", Encoding.UTF8, "application/json");

这取决于您有什么内容。您需要使用新的HttpContent初始化您的requestMessage.Content属性。例如：

...
// Add request body
if (isPostRequest)
{
    requestMessage.Content = new ByteArrayContent(content);
}
...

其中content是您的编码内容。您还应该包括正确的Content-type头。

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