通过PHP SDK 2从S3抓取对象的内容。
通过PHP SDK 2从S3抓取对象的内容。
我一直在尝试找出如何从S3存储桶中获取内容,以便将其包含在一个ZipArchive中,以供客户使用。他们现在需要创建报告,其中包含由客户推送到S3的文件。我已经尝试了使用PHP SDK 2 API(安装在PEAR中)的以下方法:
require 'AWSSDKforPHP/aws.phar'; use Aws\S3\S3Client; use Aws\Common\Enum\Region; $config = array( 'key' => 'the-aws-key', 'secret' => 'the-aws-secret', 'region' => Region::US_EAST_1 ); $aws_s3 = S3Client::factory($config); $app_config['s3']['bucket'] = 'the-aws-bucket'; $app_config['s3']['prefix'] = ''; $attach_name = 'hosted-test-file.jpg'; try { $result = $aws_s3->getObject( array( 'Bucket' => $app_config['s3']['bucket'], 'Key' => $app_config['s3']['prefix'].$attach_name ) ); var_dump($result); $body = $result->get('Body'); var_dump($body); $handle = fopen('php://temp', 'r'); $content = stream_get_contents($handle); echo "String length: ".strlen($content); } catch(Aws\S3\Exception\S3Exception $e) { echo "Request failed."; }
然而,它只返回一个`Guzzle\Http\EntityBody`对象,不确定如何获取实际内容,以便将其推送到zip文件中。
[获取对象](http://docs.amazonwebservices.com/aws-sdk-php-2/latest/class-Aws.S3.S3Client.html#_getObject)
object(Guzzle\Service\Resource\Model)[126] protected 'structure' => object(Guzzle\Service\Description\Parameter)[109] protected 'name' => null protected 'description' => null protected 'type' => string 'object' (length = 6) protected 'required' => boolean false protected 'enum' => null protected 'additionalProperties' => boolean true protected 'items' => null protected 'parent' => null protected 'ref' => null protected 'format' => null protected 'data' => array (size = 11) 'Body' => object(Guzzle\Http\EntityBody)[97] protected 'contentEncoding' => boolean false protected 'rewindFunction' => null protected 'stream' => resource(292, stream) protected 'size' => int 3078337 protected 'cache' => array (size = 9) ... 'DeleteMarker' => string '' (length = 0) 'Expiration' => string '' (length = 0) 'WebsiteRedirectLocation' => string '' (length = 0) 'LastModified' => string 'Fri, 30 Nov 2012 21:07:30 GMT' (length = 29) 'ContentType' => string 'binary/octet-stream' (length = 19) 'ContentLength' => string '3078337' (length = 7) 'ETag' => string '"the-etag-of-the-file"' (length = 34) 'ServerSideEncryption' => string '' (length = 0) 'VersionId' => string '' (length = 0) 'RequestId' => string 'request-id' (length = 16)
[返回的Body](http://docs.amazonwebservices.com/aws-sdk-php-2/latest/class-Guzzle.Http.EntityBody.html)
object(Guzzle\Http\EntityBody)[96] protected 'contentEncoding' => boolean false protected 'rewindFunction' => null protected 'stream' => resource(292, stream) protected 'size' => int 3078337 protected 'cache' => array (size = 9) 'wrapper_type' => string 'php' (length = 3) 'stream_type' => string 'temp' (length = 4) 'mode' => string 'w+b' (length = 3) 'unread_bytes' => int 0 'seekable' => boolean true 'uri' => string 'php://temp' (length = 10) 'is_local' => boolean true 'is_readable' => boolean true 'is_writable' => boolean true // Echo of strlen() String length: 0
任何信息都会非常感激,谢谢!
解决方案:
我花了一些时间才找到解决方法,但我能找到一个指引我正确方向的gist,为了获取文件的内容,你需要做以下操作:
require 'AWSSDKforPHP/aws.phar'; use Aws\S3\S3Client; use Aws\Common\Enum\Region; $config = array( 'key' => 'the-aws-key', 'secret' => 'the-aws-secret', 'region' => Region::US_EAST_1 ); $aws_s3 = S3Client::factory($config); $app_config['s3']['bucket'] = 'the-aws-bucket'; $app_config['s3']['prefix'] = ''; $attach_name = 'hosted-test-file.jpg'; try { $result = $aws_s3->getObject( array( 'Bucket' => $app_config['s3']['bucket'], 'Key' => $app_config['s3']['prefix'].$attach_name ) ); $body = $result->get('Body'); $body->rewind(); $content = $body->read($result['ContentLength']); } catch(Aws\S3\Exception\S3Exception $e) { echo "Request failed."; }