如何在Python 3中处理urllib的超时？

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如何在Python 3中处理urllib的超时？

首先，我的问题与这个问题非常相似。我希望urllib.urlopen()的超时能够引发一个我可以处理的异常。

这难道不属于URLError吗？

try:
    response = urllib.request.urlopen(url, timeout=10).read().decode('utf-8')
except (HTTPError, URLError) as error:
    logging.error(
        '无法获取%s的数据，因为%s\nURL：%s', name, error, url)
else:
    logging.info('访问成功。')

错误信息：

resp = urllib.request.urlopen(req, timeout=10).read().decode('utf-8')

File "/usr/lib/python3.2/urllib/request.py", line 138, in urlopen

return opener.open(url, data, timeout)

File "/usr/lib/python3.2/urllib/request.py", line 369, in open

response = self._open(req, data)

File "/usr/lib/python3.2/urllib/request.py", line 387, in _open

'_open', req)

File "/usr/lib/python3.2/urllib/request.py", line 347, in _call_chain

result = func(*args)

File "/usr/lib/python3.2/urllib/request.py", line 1156, in http_open

return self.do_open(http.client.HTTPConnection, req)

File "/usr/lib/python3.2/urllib/request.py", line 1141, in do_open

r = h.getresponse()

File "/usr/lib/python3.2/http/client.py", line 1046, in getresponse

response.begin()

File "/usr/lib/python3.2/http/client.py", line 346, in begin

version, status, reason = self._read_status()

File "/usr/lib/python3.2/http/client.py", line 308, in _read_status

line = str(self.fp.readline(_MAXLINE + 1), "iso-8859-1")

File "/usr/lib/python3.2/socket.py", line 276, in readinto

return self._sock.recv_into(b)

socket.timeout: 超时

在Python 3中，对urllib和urllib2模块进行了重组，合并为urllib。可能是这个变化导致了这个问题吗？

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