Typescript: TS7006: 参数'xxx' 隐式具有 'any' 类型

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Typescript: TS7006: 参数'xxx' 隐式具有 'any' 类型

在测试我的UserRouter时，我正在使用一个json文件

data.json

[
  {
    "id": 1,
    "name": "Luke Cage",
    "aliases": ["Carl Lucas", "Power Man", "Mr. Bulletproof", "Hero for Hire"],
    "occupation": "bartender",
    "gender": "male",
    "height": {
      "ft": 6,
      "in": 3
    },
    "hair": "bald",
    "eyes": "brown",
    "powers": [
      "strength",
      "durability",
      "healing"
    ]
  },
  {
  ...
  }
]

构建我的应用程序时，我得到以下TS错误

ERROR in ...../UserRouter.ts
(30,27): error TS7006: Parameter 'user' implicitly has an 'any' type.

UserRouter.ts

import {Router, Request, Response, NextFunction} from 'express';
const Users = require('../data');
export class UserRouter {
  router: Router;
  constructor() {
  ...
  }
  /**
   * GET one User by id
   */
  public getOne(req: Request, res: Response, _next: NextFunction) {
    let query = parseInt(req.params.id);
 /*[30]->*/let user = Users.find(user => user.id === query);
    if (user) {
      res.status(200)
        .send({
          message: 'Success',
          status: res.status,
          user
        });
    }
    else {
      res.status(404)
        .send({
          message: 'No User found with the given id.',
          status: res.status
        });
    }
  }
}
const userRouter = new UserRouter().router;
export default userRouter;

admin 更改状态以发布 2023年5月23日
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2 答案

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在您的tsconfig.json文件中，在compilerOptions下设置参数"noImplicitAny": false，以消除此错误。

0
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您正在使用--noImplicitAny选项，而TypeScript不了解Users对象的类型。在这种情况下，您需要明确定义user类型。

更改这行代码:

let user = Users.find(user => user.id === query);

改为:

let user = Users.find((user: any) => user.id === query); 
// use "any" or some other interface to type this argument

或者定义您的Users对象的类型:

//...
interface User {
    id: number;
    name: string;
    aliases: string[];
    occupation: string;
    gender: string;
    height: {ft: number; in: number;}
    hair: string;
    eyes: string;
    powers: string[]
}
//...
const Users = require('../data');
//...

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