在使用VBA将公式写入单元格时出现语法错误。

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在使用VBA将公式写入单元格时出现语法错误。

不熟悉Visual Basic,但参考了一些资料来解决这个问题。我想问一下,因为我花了一个小时来弄清楚如何解决这个问题,也许我需要一些建议。在为Excel创建宏时,我遇到了这个错误。起初它是工作的,但在我添加了一些行之后,语法变成了红色,并且运行宏时出现了一个

编译错误:语法错误

Range("D2").Select
ActiveCell.FormulaR1C1 = _
    "=IF(ISNUMBER(SEARCH(""California"",RC[-2],1)),""California"", 
    IF(ISNUMBER(SEARCH(""Florida"",RC[-2],1)),""Florida"", 
    IF(ISNUMBER(SEARCH(""Texas"",RC[-2],1)),""Texas"", IF(ISNUMBER(SEARCH(""New 
    Mexico"",RC[-2],1)),""New Mexico"", IF(ISNUMBER(SEARCH(""Alaska"",RC[-2],1)),""Alaska"", 
    IF(ISNUMBER(SEARCH(""New Jersey"",RC[-2],1)),""New Jersey"",
    """"))))))&IF(ISNUMBER(SEARCH(""Marikina"",RC[-2],1)),""Marikina"", 
    IF(ISNUMBER(SEARCH(""Maryland"",RC[-2],1)),""Maryland"", 
    IF(ISNUMBER(SEARCH(""Nebraska"",RC[-2],1)),""Nebraska"", 
    IF(ISNUMBER(SEARCH(""Pennsylvania"",RC[-2],1)),""Pennsylvania"",   
    IF(ISNUMBER(SEARCH(""Illinois"",RC[-2],1)),""Illinois"",
    IF(ISNUMBER(SEARCH(""Colorado"",RC[-2],1)),""Colorado"",""""))))))&
    IF(ISNUMBER(SEARCH(""Louisiana"",RC[-2],1)),""Louisiana"", 
    IF(ISNUMBER(SEARCH(""Idaho"",RC[-2],1)),""Idaho"", 
    IF(ISNUMBER(SEARCH(""Hawaii"",RC[-2],1)),""Hawaii"", 
    IF(ISNUMBER(SEARCH(""Vermont"",RC[-2],1)),""Vermont"", 
    IF(ISNUMBER(SEARCH(""West Virginia"",RC[-2],1)),""West Virginia"",           
    IF(ISNUMBER(SEARCH(""Connecticut"",RC[-2],1)), 
    ""Connecticut"","""")))))"
Range("D2").Select
 Selection.AutoFill Destination:=Range("D2:D38"), Type:=xlFillDefault
 Range("D2:D38").Select
 ActiveWindow.SmallScroll Down:=-39
End Sub

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Syntax Error trying to write a formula into a cell with VBA的问题是,无法直接添加换行符,需要将公式拆分成多个字符串,并使用&符号将它们连接起来。换行符需要使用_在行尾进行连接。

解决方法是创建一个函数,可以根据州名列表生成公式。首先创建一个存储州名的数组(ListOfStates),然后使用Join函数将所有块通过&连接起来,最后将生成的公式赋值给指定的单元格。

代码如下:

Option Explicit
Public Sub Example()
    Dim ListOfStates() As Variant
    ListOfStates = Array("California", "Florida", "Texas", "New Mexico", "Alaska", "New Jersey", "Marikina", "Maryland", "Nebraska", "Pennsylvania", "Illinois", "Colorado", "Louisiana", "Idaho", "Hawaii", "Vermont", "West Virginia", "Connecticut")
    Range("D2").FormulaR1C1 = "=" & Join(CreateFormulaBlocks(ListOfStates), "&") 'join all blocks by &
End Sub
' returns an array of all blocks (each 6 states)
'
Public Function CreateFormulaBlocks(ByVal ListOfStates As Variant, Optional ByVal MaxPerBlock As Long = 6) As Variant
    ' how many blocks do we need
    Dim MaxBlocks As Long
    MaxBlocks = (UBound(ListOfStates) + 1) \ 6  ' note this is no normal division / but an integer division \
    ' create array for blocks
    Dim ReturnBlocks() As Variant
    ReDim ReturnBlocks(MaxBlocks - 1) As Variant
    ' create blocks
    Dim iBlock As Long
    For iBlock = 0 To MaxBlocks - 1
        Dim BlockStates() As Variant
        ReDim BlockStates(MaxPerBlock - 1) As Variant
        Dim iState As Long
        For iState = 0 To MaxPerBlock - 1
            BlockStates(iState) = ListOfStates(iBlock * 6 + iState)
        Next iState
        ' create one block of 6 states
        ReturnBlocks(iBlock) = CreateFromulaBlock(BlockStates)
    Next iBlock
    ' return all blocks as array
    CreateFormulaBlocks = ReturnBlocks
End Function
' returns one block of 6 states
' eg IF(ISNUMBER(SEARCH("California",RC[-2],1)),"California", IF(ISNUMBER(SEARCH("Florida",RC[-2],1)),"Florida", IF(ISNUMBER(SEARCH("Texas",RC[-2],1)),"Texas", IF(ISNUMBER(SEARCH("New Mexico",RC[-2],1)),"New Mexico", IF(ISNUMBER(SEARCH("Alaska",RC[-2],1)),"Alaska", IF(ISNUMBER(SEARCH("New Jersey",RC[-2],1)),"New Jersey", ""))))))
'
Public Function CreateFromulaBlock(ByVal States As Variant) As String
    Dim FormulaString As String
    Dim State As Variant
    For Each State In States
        FormulaString = FormulaString & "IF(ISNUMBER(SEARCH(""" & State & """,RC[-2],1)),""" & State & """, "
    Next State
    CreateFromulaBlock = FormulaString & """""" & String(UBound(States) + 1, ")")
End Function

这样可以解决问题。但是需要注意,如果在代码中添加太多的行连接符" _",会出现"Too many line continuations"错误。这是因为VBA对行连接符的数量有限制。为了避免这个问题,可以使用上述的函数生成公式,只需将州名添加到列表中即可。

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