Android HTTP GET错误
Android HTTP GET错误
抱歉，我是Java和Android的新手。\n我想了解为什么它总是出现错误。\n谢谢！\n
try {
HttpClient client = new DefaultHttpClient();
String getURL = "http://www.google.com";
HttpGet get = new HttpGet(getURL);
HttpResponse responseGet = client.execute(get);
HttpEntity resEntityGet = responseGet.getEntity();
if (resEntityGet != null) {
Toast.makeText(getApplicationContext(), "ok", Toast.LENGTH_LONG).show();
}
} catch (Exception e) {
//e.printStackTrace();
Toast.makeText(getApplicationContext(), "error", Toast.LENGTH_LONG).show();
}
\n导入\n
import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.client.HttpClient; import org.apache.http.client.methods.HttpGet; import org.apache.http.impl.client.DefaultHttpClient;
\n是的，我已经输入了网络权限。\n
问题原因：在Android中使用HTTP GET请求时出现错误。
解决方法：修改代码，使用正确的HTTP GET请求方法。
在Android开发中，我们经常需要使用HTTP请求与服务器进行通信。下面是一段用于发送HTTP请求的代码示例：
public class RequestClient extends AsyncTask<String, Void, String>{
Context context;
public RequestClient(Context c) {
context = c;
}
protected void onPreExecute() {
super.onPreExecute();
}
protected String doInBackground(String... aurl){
String responseString="";
HttpClient client = null;
try {
client = new DefaultHttpClient();
HttpGet get = new HttpGet(LoginActivity.url);
HttpResponse responseGet = client.execute(get);
HttpEntity resEntityGet = responseGet.getEntity();
if (resEntityGet != null) {
responseString = EntityUtils.toString(resEntityGet);
Log.i("GET RESPONSE", responseString.trim());
}
} catch (Exception e) {
Log.d("ANDRO_ASYNC_ERROR", "Error is "+e.toString());
}
Log.d("ANDRO_ASYNC_RESPONSE", responseString.trim());
client.getConnectionManager().shutdown();
return responseString.trim();
}
protected void onPostExecute(String response) {
super.onPostExecute(response);
}
}
然而，在使用这段代码发送HTTP GET请求时，可能会遇到错误。为了解决这个问题，我们需要修改代码中的HTTP GET请求方法。
具体的修改方法如下：
public class RequestClient extends AsyncTask<String, Void, String>{
Context context;
public RequestClient(Context c) {
context = c;
}
protected void onPreExecute() {
super.onPreExecute();
}
protected String doInBackground(String... aurl){
String responseString="";
HttpURLConnection connection = null;
try {
URL url = new URL(LoginActivity.url);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("GET");
connection.connect();
int responseCode = connection.getResponseCode();
if (responseCode == HttpURLConnection.HTTP_OK) {
InputStream inputStream = connection.getInputStream();
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = reader.readLine()) != null) {
stringBuilder.append(line);
}
responseString = stringBuilder.toString();
inputStream.close();
reader.close();
}
} catch (Exception e) {
Log.d("ANDRO_ASYNC_ERROR", "Error is "+e.toString());
}
Log.d("ANDRO_ASYNC_RESPONSE", responseString.trim());
if (connection != null) {
connection.disconnect();
}
return responseString.trim();
}
protected void onPostExecute(String response) {
super.onPostExecute(response);
}
}
通过修改后的代码，我们可以正确地发送HTTP GET请求，并从服务器获取响应数据。这样就解决了Android中使用HTTP GET请求时出现的错误。
