SimpleXML抛出XmlPullParserException，没有理由地引发未终止的实体引用。
SimpleXML抛出XmlPullParserException，没有理由地引发未终止的实体引用。
我对问题的原因已经没有任何想法了..我在Android上使用SimpleXML，它抛出了以下的堆栈跟踪：\n
06-08 13:20:56.450: E/AndroidRuntime(2281): FATAL EXCEPTION: main 06-08 13:20:56.450: E/AndroidRuntime(2281): java.lang.RuntimeException: org.xmlpull.v1.XmlPullParserException: unterminated entity ref (position:TEXT ????T???????????????...@21:133 in java.io.BufferedReader@b6438630) 06-08 13:20:56.450: E/AndroidRuntime(2281): at com.example.stuff.manager.LevelManager.(LevelManager.java:32) 06-08 13:20:56.450: E/AndroidRuntime(2281): at com.example.stuff.fragment.MainMenuFragment.onClick(MainMenuFragment.java:138) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.view.View.performClick(View.java:2485) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.view.View$PerformClick.run(View.java:9080) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.os.Handler.handleCallback(Handler.java:587) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.os.Handler.dispatchMessage(Handler.java:92) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.os.Looper.loop(Looper.java:130) 06-08 13:20:56.450: E/AndroidRuntime(2281): at android.app.ActivityThread.main(ActivityThread.java:3683) 06-08 13:20:56.450: E/AndroidRuntime(2281): at java.lang.reflect.Method.invokeNative(Native Method) 06-08 13:20:56.450: E/AndroidRuntime(2281): at java.lang.reflect.Method.invoke(Method.java:507) 06-08 13:20:56.450: E/AndroidRuntime(2281): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839) 06-08 13:20:56.450: E/AndroidRuntime(2281): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597) 06-08 13:20:56.450: E/AndroidRuntime(2281): at dalvik.system.NativeStart.main(Native Method) 06-08 13:20:56.450: E/AndroidRuntime(2281): Caused by: org.xmlpull.v1.XmlPullParserException: unterminated entity ref (position:TEXT ????T???????????????...@21:133 in java.io.BufferedReader@b6438630) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.exception(KXmlParser.java:273) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.error(KXmlParser.java:269) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.pushEntity(KXmlParser.java:781) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.pushText(KXmlParser.java:849) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.nextImpl(KXmlParser.java:354) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.kxml2.io.KXmlParser.next(KXmlParser.java:1378) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.PullReader.read(PullReader.java:105) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.PullReader.next(PullReader.java:89) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.NodeReader.readElement(NodeReader.java:111) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.NodeReader.readRoot(NodeReader.java:85) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.NodeBuilder.read(NodeBuilder.java:84) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.stream.NodeBuilder.read(NodeBuilder.java:71) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.core.Persister.read(Persister.java:562) 06-08 13:20:56.450: E/AndroidRuntime(2281): at org.simpleframework.xml.core.Persister.read(Persister.java:462) 06-08 13:20:56.450: E/AndroidRuntime(2281): at com.example.stuff.manager.LevelManager. (LevelManager.java:27) 06-08 13:20:56.450: E/AndroidRuntime(2281): ... 12 more
\n从以下XML文件加载：\n
\n我使用以下POJO作为XML中内容的容器：\nFruitData.java:\n
@Root
public class Fruitdata
{
@Attribute
private Integer id;
@Attribute
private Integer row;
@Attribute
private Integer column;
public Integer getId()
{
return id;
}
public void setId(Integer id)
{
this.id = id;
}
public int getRow()
{
return row;
}
public void setRow(int row)
{
this.row = row;
}
public int getColumn()
{
return column;
}
public void setColumn(int column)
{
this.column = column;
}
}
\nFruitDatas.java:\n
@Root
public class Fruitdatas
{
@ElementList
private List fruitdatas;
public Fruitdatas()
{
}
public Fruitdatas(@ElementList(name = "fruitdatas") List fruitdatas)
{
this.fruitdatas = fruitdatas;
}
public List getFruitdatas()
{
return fruitdatas;
}
public void setFruitdatas(List fruitdatas)
{
this.fruitdatas = fruitdatas;
}
}
\nLevel.java:\n
@Root
public class Level
{
@Attribute
private Long id;
@Attribute
private Long time;
@ElementList
private List fruitdatas;
public Long getId()
{
return id;
}
public void setId(Long id)
{
this.id = id;
}
public Long getTime()
{
return time;
}
public void setTime(Long time)
{
this.time = time;
}
public List getFruitdatas()
{
return fruitdatas;
}
public void setFruitdatas(List fruits)
{
this.fruitdatas = fruits;
}
}
\nLevels.java:\n
@Root
public class Levels
{
@ElementList
private List levels;
public Levels()
{
}
public Levels(@ElementList(name = "levels") List levels)
{
this.levels = levels;
}
public List getLevels()
{
return levels;
}
public void setLevels(List levels)
{
this.levels = levels;
}
}
\n加载发生在这里：\n
public LevelManager()
{
Serializer serializer = new Persister();
Levels levels = null;
BufferedReader br = null;
try
{
br = new BufferedReader(new InputStreamReader(Thread.currentThread().getContextClassLoader().getResourceAsStream("res/xml/levels.xml")));
levels = serializer.read(Levels.class, br);
}
catch (Exception e)
{
Log.e(getClass().getSimpleName(), "Error in deserialization.", e);
throw new RuntimeException(e);
}
finally
{
if (br != null)
{
try
{
br.close();
}
catch (IOException e)
{
}
}
}
if (levels != null)
{
this.levels = levels.getLevels();
}
}
\n我也尝试过只使用InputStream，但是我得到了相同的错误。\n我搜索了答案，但总是发现XML中有未转义的字符。我甚至检查了抛出异常的xml解析器的源代码，但它对我没有多大帮助：\n
723 private final void More ...pushEntity()
724 throws IOException, XmlPullParserException {
725
726 push(read()); // &
727
728
729 int pos = txtPos;
730
731 while (true) {
732 int c = read();
733 if (c == ';')
734 break;
735 if (c < 128
736 && (c < '0' || c > '9')
737 && (c < 'a' || c > 'z')
738 && (c < 'A' || c > 'Z')
739 && c != '_'
740 && c != '-'
741 && c != '#') {
742 if(!relaxed){
743 error("unterminated entity ref");
744 }
745 //; ends with:"+(char)c);
746 if (c != -1)
747 push(c);
748 return;
749 }
750
751 push(c);
752 }
753
754 String code = get(pos);
755 txtPos = pos - 1;
756 if (token && type == ENTITY_REF){
757 name = code;
758 }
759
760 if (code.charAt(0) == '#') {
761 int c =
762 (code.charAt(1) == 'x'
763 ? Integer.parseInt(code.substring(2), 16)
764 : Integer.parseInt(code.substring(1)));
765 push(c);
766 return;
767 }
768
769 String result = (String) entityMap.get(code);
770
771 unresolved = result == null;
772
773 if (unresolved) {
774 if (!token)
775 error("unresolved: &" + code + ";");
776 }
777 else {
778 for (int i = 0; i < result.length(); i++)
779 push(result.charAt(i));
780 }
781 }
\n我不知道!relaxed是什么意思。因此，我完全无法想到如何解决这个问题。\n有人之前遇到过这个问题吗？我可能做错了什么？我甚至连我的XML都是有效的。我认为我也正确地注释了这些类。有什么想法吗？\n编辑：显然我的调试感觉到了，我将缓冲区读入的内容通过System.out发送出去。\n结果：\n
06-08 13:47:51.830: I/System.out(2334): ????T???????????????????????????????????h?????????????????????? ????????????????????????!??????'??????4??????@??????D??????J??????S??????W??????[??????_??????c??????g??????k??????o??????levels??id??time??level??1??400?? 06-08 13:47:51.830: I/System.out(2334): fruitdatas?? fruitdata??0??row??column??2??4??3??5??6??7??8??9??????$??????????????????????????????????????????????????L???????????????????????????????????????????????????????????????????????????????????????????????$????????????????????????????????????????????????$????????????????????????????????????????????????$??????????????????????????????????????????????????????????????????????????????????????????????????????????????????$???????????????????? ?????????????????????????????????????????????????????????????????????????????????????? ????????$???????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????? ??????????????????????$?????? 06-08 13:47:51.830: I/System.out(2334): ??????????????????????????????????????????$??????????????????????????????????????????????????????????????????????????????????????????????????????????????$???????????????????? ?????????????????????????????????????????????????????????????????????????????????????? ????????$????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 06-08 13:47:51.830: I/System.out(2334): ?????????????????????????????????????????????????????????????????????????????????????? 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\n我将尝试弄清楚为什么从流中读取的XML是无意义的....
SimpleXML throws XmlPullParserException, unterminated entity ref for no reason
最近我遇到了一个问题，经过我的调试，我终于找到了解决方法。原来，使用以下代码读取数据是一个非常糟糕的主意。
br = new BufferedReader(new InputStreamReader(Thread.currentThread().getContextClassLoader().getResourceAsStream("res/xml/levels.xml")));
解决方法是将XML文件放入/res/raw文件夹中，并使用原始资源方式打开它们。
public LevelManager(Context context)
{
Serializer serializer = new Persister();
Levels levels = null;
BufferedReader br = null;
try
{
br = new BufferedReader(new InputStreamReader(context.getResources().openRawResource(R.raw.levels)));
levels = serializer.read(Levels.class, br);
}
catch (Exception e)
{
Log.e(getClass().getSimpleName(), "Error in deserialization.", e);
throw new RuntimeException(e);
}
finally
{
if (br != null)
{
IOUtils.closeQuietly(br);
}
}
}
这样，文件的内容就可以正确地读取了。
希望这个解决方法能够帮助到其他人，不要再浪费时间在这个问题上了。
另外，我还需要添加`inline=true`，否则根据我的XML结构，它找不到数据。但这与问题没有直接关系。